modify code

pull/6/head
左程云 5 years ago
parent 4b5e1e0e59
commit f89dea02b9

@ -5,7 +5,7 @@ import java.util.Comparator;
import java.util.HashMap; import java.util.HashMap;
// OJ链接https://www.lintcode.com/problem/topological-sorting // OJ链接https://www.lintcode.com/problem/topological-sorting
public class Code03_TopologicalOrderDFS { public class Code03_TopologicalOrderDFS1 {
// 不要提交这个类 // 不要提交这个类
public static class DirectedGraphNode { public static class DirectedGraphNode {

@ -0,0 +1,70 @@
package class10;
import java.util.ArrayList;
import java.util.Comparator;
import java.util.HashMap;
// OJ链接https://www.lintcode.com/problem/topological-sorting
public class Code03_TopologicalOrderDFS2 {
// 不要提交这个类
public static class DirectedGraphNode {
public int label;
public ArrayList<DirectedGraphNode> neighbors;
public DirectedGraphNode(int x) {
label = x;
neighbors = new ArrayList<DirectedGraphNode>();
}
}
// 提交下面的
public static class Record {
public DirectedGraphNode node;
public long nodes;
public Record(DirectedGraphNode n, long o) {
node = n;
nodes = o;
}
}
public static class MyComparator implements Comparator<Record> {
@Override
public int compare(Record o1, Record o2) {
return o1.nodes == o2.nodes ? 0 : (o1.nodes > o2.nodes ? -1 : 1);
}
}
public static ArrayList<DirectedGraphNode> topSort(ArrayList<DirectedGraphNode> graph) {
HashMap<DirectedGraphNode, Record> order = new HashMap<>();
for (DirectedGraphNode cur : graph) {
f(cur, order);
}
ArrayList<Record> recordArr = new ArrayList<>();
for (Record r : order.values()) {
recordArr.add(r);
}
recordArr.sort(new MyComparator());
ArrayList<DirectedGraphNode> ans = new ArrayList<DirectedGraphNode>();
for (Record r : recordArr) {
ans.add(r.node);
}
return ans;
}
public static Record f(DirectedGraphNode cur, HashMap<DirectedGraphNode, Record> order) {
if (order.containsKey(cur)) {
return order.get(cur);
}
long nodes = 0;
for (DirectedGraphNode next : cur.neighbors) {
nodes += f(next, order).nodes;
}
Record ans = new Record(cur, nodes + 1);
order.put(cur, ans);
return ans;
}
}
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