【Fix Speech Issue No.8】issue 3652 merge_yi function has a bug

paddlespeech/t2s/frontend/tone_sandhi.py

@@ -237,26 +237,26 @@ class ToneSandhi():
     # output seg: [['听一听', 'v']]
     def _merge_yi(self, seg: List[Tuple[str, str]]) -> List[Tuple[str, str]]:
         new_seg = []
-    skip_next = False
+        skip_next = False
-    # function 1
+        # function 1
-    for i, (word, pos) in enumerate(seg):
+        for i, (word, pos) in enumerate(seg):
-        if skip_next:
+            if skip_next:
-            skip_next = False
+                skip_next = False
-            continue
+                continue
-        if i - 1 >= 0 and word == "一" and i + 1 < len(seg) and seg[i - 1][0] == seg[i + 1][0] and seg[i - 1][1] == "v":
+            if i - 1 >= 0 and word == "一" and i + 1 < len(seg) and seg[i - 1][0] == seg[i + 1][0] and seg[i - 1][1] == "v":
-            new_seg[-1] = (new_seg[-1][0] + "一" + seg[i + 1][0], new_seg[-1][1])
+                new_seg[-1] = (new_seg[-1][0] + "一" + seg[i + 1][0], new_seg[-1][1])
-            skip_next = True
+                skip_next = True
-        else:
+            else:
-            new_seg.append((word, pos))
+                new_seg.append((word, pos))
-    seg = new_seg
+        seg = new_seg
-    new_seg = []
+        new_seg = []
-    # function 2
+        # function 2
-    for i, (word, pos) in enumerate(seg):
+        for i, (word, pos) in enumerate(seg):
-        if new_seg and new_seg[-1][0] == "一":
+            if new_seg and new_seg[-1][0] == "一":
-            new_seg[-1] = (new_seg[-1][0] + word, new_seg[-1][1])
+                new_seg[-1] = (new_seg[-1][0] + word, new_seg[-1][1])
-        else:
+            else:
-            new_seg.append((word, pos))
+                new_seg.append((word, pos))
-    return new_seg
+        return new_seg
 
     # the first and the second words are all_tone_three
     def _merge_continuous_three_tones(