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// declare empty array
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let arr = new Array();
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let arr1 = new Array(6)
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// find length of array
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console.log(arr1.length)
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// get the first, middle and last item of the array
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arr1 = [1,2,3,4,5,6]
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let first = arr1[0];
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let last = arr1[arr1.length-1]
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let middle = arr1[arr1.length/2-1]
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console.log(`first: ${first} \nmiddle: ${middle} \nlast: ${last}`)
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//
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itCompanies = ['Facebook','Google','Microsoft','Apple','IBM','Oracle','Amazon']
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console.log(itCompanies)
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// print each company
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for(const company of itCompanies){
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console.log(company)
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}
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console.log("\n")
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itCompanies.forEach(element => {
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console.log(element)
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});
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// change the company name to uppercase and print one by one
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itCompanies.forEach(element => {
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element = element.toUpperCase()
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console.log(element)
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});
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let company1 = 'Amazon'
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let company2 = 'PayPal'
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if(itCompanies.includes(company2)){
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console.log("The IT company is " + company1)
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}
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else{
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console.log("It is not an IT company")
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}
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// Filter out companies which have more than one 'o' without the filter method
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// sort the array using sort method - the sorting is based on alphabetical order
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console.log(itCompanies.sort())
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// slicing the first three companies from the array
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console.log(itCompanies.splice(0,3))
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// slicing the last three companies from the array
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console.log(itCompanies.splice(arr.length-3))
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// -----------------------------------------------------------------------------
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// EXERCISE: LEVEL 2
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@ -0,0 +1,5 @@
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if(itCompanies.includes(company1)){
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// console.log("The IT company is" + company1)
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// }
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// else{
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// co
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