Merge 3dfd1b2750 into 09f408a1b7

solutions/day-01/level1.js

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+// 1. Declare an empty array;
+let countries = []
+// 2. Declare an array with more than 5 number of elements
+countries = [
+  'Albania',
+  'Bolivia',
+  'Canada',
+  'Denmark',
+  'Ethiopia',
+  'Finland',
+  'Germany',
+  'Hungary',
+  'Ireland',
+  'Japan',
+  'Kenya',
+]
+
+// 3. Find the length of your array
+console.log(countries.length)
+
+// 4. Get the first item, the middle item and the last item of the array
+console.log(countries[0])
+console.log(countries[Math.floor(countries.length / 2)])
+console.log(countries[countries.length - 1])
+
+// 5. Declare an array called mixedDataTypes,put different data types in the array and find the length of the array. The array size should be greater than 5
+let mixedDataTypes = ['Albania', 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
+console.log(mixedDataTypes.length)
+
+// 6. Declare an array variable name itCompanies and assign initial values Facebook, Google, Microsoft, Apple, IBM, Oracle and Amazon
+let itCompanies = [
+  'Facebook',
+  'Google',
+  'Microsoft',
+  'Apple',
+  'IBM',
+  'Oracle',
+  'Amazon',
+]
+
+// 7. Print the array using console.log()
+console.log(itCompanies)
+
+// 8. Print the number of companies in the array
+console.log(itCompanies.length)
+
+// 9. Print the first company, middle and last company
+console.log(itCompanies[0])
+console.log(itCompanies[Math.floor(itCompanies.length / 2)])
+console.log(itCompanies[itCompanies.length - 1])
+
+// 10. Print out each company
+for (let i = 0; i < itCompanies.length; i++) {
+  console.log(itCompanies[i])
+}
+
+// 11. Change each company name to uppercase one by one and print them out
+for (let i = 0; i < itCompanies.length; i++) {
+  console.log(itCompanies[i].toUpperCase())
+}
+
+// 12. Print the array like as a sentence: Facebook, Google, Microsoft, Apple, IBM,Oracle and Amazon are big IT companies.
+let sentence = ''
+for (let i = 0; i < itCompanies.length; i++) {
+  if (i === itCompanies.length - 1) {
+    sentence += 'and ' + itCompanies[i]
+  } else {
+    sentence += itCompanies[i] + ', '
+  }
+}
+
+// 13. Check if a certain company exists in the itCompanies array. If it exist return the company else return a company is not found
+function checkCompany(company) {
+  for (let i = 0; i < itCompanies.length; i++) {
+    if (itCompanies[i] === company) {
+      return company
+    }
+    return 'Company is not found'
+  }
+}
+
+// 14. Filter out companies which have more than one 'o' without the filter method
+function filterCompanies() {
+  let filteredCompanies = []
+  for (let i = 0; i < itCompanies.length; i++) {
+    let count = 0
+    for (let j = 0; j < itCompanies[i].length; j++) {
+      if (itCompanies[i][j] === 'o') {
+        count++
+      }
+    }
+    if (count > 1) {
+      filteredCompanies.push(itCompanies[i])
+    }
+  }
+  return filteredCompanies
+}
+
+// 15. Sort the array using sort() method
+itCompanies.sort()
+
+// 16. Reverse the array using reverse() method
+
+itCompanies.reverse()
+
+// 17. Slice out the first 3 companies from the array
+
+itCompanies.slice(0, 3)
+
+// 18. Slice out the last 3 companies from the array
+itCompanies.slice(itCompanies.length - 3)
+
+// 19. Slice out the middle IT company or companies from the array
+itCompanies.slice(Math.floor(itCompanies.length / 2), 1)
+
+// 20. Remove the first IT company from the array
+itCompanies.shift()
+
+// 21. Remove the middle IT company or companies from the array
+itCompanies.splice(Math.floor(itCompanies.length / 2), 1).shift()
+
+// 22. Remove the last IT company from the array
+itCompanies.slice(itCompanies.length - 1).shift()
+
+// 23. Remove all IT companies
+
+itCompanies = []