Helder Cambuta
3 years ago
parent
11fda60bb9
commit
8ad787242b
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<!DOCTYPE html>
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<html lang="en">
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<head>
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<meta charset="UTF-8">
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<meta http-equiv="X-UA-Compatible" content="IE=edge">
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<meta name="viewport" content="width=device-width, initial-scale=1.0">
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<title>Level 1 Exercise</title>
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</head>
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<body>
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<script src="./level1.js"></script>
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</body>
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</html>
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/**
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* 1. Get user input using prompt(“Enter your age:”). If user is 18 or older,
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* give feedback:'You are old enough to drive' but if not 18 give another
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* feedback stating to wait for the number of years he needs to turn 18.
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*
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*/
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let age = Number(prompt('Enter your age: '))
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if (age >= 18) {
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console.log('You are old enough to drive.')
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} else {
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console.log(`You are left with ${18 - age} years to drive.`)
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}
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/**
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* 2. Compare the values of myAge and yourAge using if … else. Based on the
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* comparison and log the result to console stating who is older (me or you).
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* Use prompt(“Enter your age:”) to get the age as input.
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*/
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let yourAge = Number(prompt('Enter your age: '))
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let myAge = 21
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if (yourAge > myAge) {
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console.log(`You are ${yourAge - myAge} years older than me.`)
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} else {
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console.log(`I'm ${myAge - yourAge} years older than you`)
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}
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/**
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* 3. If a is greater than b return 'a is greater than b' else
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* 'a is less than b'. Try to implement it in two ways
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*/
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let a = 4
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let b = 3
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a > b
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? console.log(`${a} is greater than ${b}`)
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: console.log(`${b} is greater than ${a}`)
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/**
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* 4. Even numbers are divisible by 2 and the remainder is zero. How do you check,
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* if a number is even or not using JavaScript?
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*/
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let number = Number(prompt('Enter a number: '))
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if (number % 2 == 0) {
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console.log(`${number} is an even number.`)
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} else {
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console.log(`${number} is an odd number.`)
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}
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@ -0,0 +1,13 @@
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<!DOCTYPE html>
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<html lang="en">
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<head>
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<meta charset="UTF-8">
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<meta http-equiv="X-UA-Compatible" content="IE=edge">
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<meta name="viewport" content="width=device-width, initial-scale=1.0">
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<title>Level 2 Exercises</title>
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</head>
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<body>
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<script src="./level2.js"></script>
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</body>
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</html>
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/**
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* 1. Write a code which can give grades to students according to theirs scores:
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* 80-100, A
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* 70-89, B
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* 60-69, C
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* 50-59, D
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* 0-49, F
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*/
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let score = Number(prompt('Enter your score: '))
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switch (true) {
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case 80 <= score && score <= 100:
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console.log('A')
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break
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case 70 <= score && score <= 79:
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console.log('B')
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break
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case 60 <= score && score <= 69:
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console.log('C')
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break
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case 50 <= score && score <= 59:
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console.log('D')
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break
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case 0 <= score && score <= 49:
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console.log('F')
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break
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default:
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console.log('Number invalid')
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}
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/**
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* 2. Check if the season is Autumn, Winter, Spring or Summer.
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* If the user input is:
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* September, October or November, the season is Autumn.
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* December, January or February, the season is Winter.
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* March, April or May, the season is Spring
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* June, July or August, the season is Summer
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*/
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let season = prompt('Whats is the month? ')
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let Autumn = ['September', 'October', 'November']
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let Winter = ['December', 'January', 'February']
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let Spring = ['March', 'April', 'May']
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let Summer = ['June', 'July', 'August']
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switch (true) {
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case Autumn.includes(season):
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console.log('The season is Autumn')
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break
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case Winter.includes(season):
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console.log('The season is Winter')
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break
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case Spring.includes(season):
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console.log('The season is Spring')
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break
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case Summer.includes(season):
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console.log('The season is Summer')
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break
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default:
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console.log('Season invalid')
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}
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/**
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* 3. Check if a day is weekend day or a working day. Your script will
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* take day as an input.
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*/
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let day = prompt('Whats is the day today? ')
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let newDay = day[0].toUpperCase()+day.slice(1, day.length).toLowerCase()
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let dayWork = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday']
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let weekend = ['Saturday', 'Sunday']
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switch (true) {
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case dayWork.includes(newDay):
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console.log(`${newDay} is a working day.`)
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break
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case weekend.includes(newDay):
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console.log(`${newDay} is a weekend.`)
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break
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default:
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console.log('Day invalid')
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}
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