Arrays exercises Level 3

solutions/day-01/level3.js

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+import { countries } from './countries.js';
+
+
+//1. The following is an array of 10 students ages:
+const ages = [19, 22, 19, 24, 20, 25, 26, 24, 25, 24]
+
+//Sort the array and find the min and max age
+const agesOrder = ages.sort();
+const minAge = agesOrder[0];
+const maxAge = agesOrder[agesOrder.length - 1];
+
+//Find the median age(one middle item or two middle items divided by two)
+const medianAge = agesOrder[agesOrder.length * 0.5];
+
+//Find the average age(all items divided by number of items)
+const averageAge; //do i need 'for' loop?
+
+//Find the range of the ages(max minus min)
+const rangeOfAges = maxAge - minAge;
+
+//Compare the value of (min - average) and (max - average), use abs() method
+
+
+//2. Slice the first ten countries from the countries array
+let sliceFirstTenCuuntries = countries.slice(0, 11);
+
+//3. Find the middle country(ies) in the countries array
+const middleCountries = countries[countries.length * 0.5];
+
+//4. Divide the countries array into two equal arrays if it is even. If countries array is not even , one more country for the first half.
+const firstCountries = countries.slice(0, countries.length * 0.5 + 1);
+const secondCountries = countries.slice(countries.length * 0.5 - 1 , countries.length - 1)