优化递归子节点

pull/17/head
RuoYi 4 years ago
parent bd7ae4e96b
commit 6b25828113

@ -269,13 +269,7 @@ public class SysDeptServiceImpl implements ISysDeptService
{
if (hasChild(list, tChild))
{
// 判断是否有子节点
Iterator<SysDept> it = childList.iterator();
while (it.hasNext())
{
SysDept n = (SysDept) it.next();
recursionFn(list, n);
}
recursionFn(list, tChild);
}
}
}

@ -178,14 +178,19 @@ public class SysMenuServiceImpl implements ISysMenuService
public List<SysMenu> buildMenuTree(List<SysMenu> menus)
{
List<SysMenu> returnList = new ArrayList<SysMenu>();
List<Long> tempList = new ArrayList<Long>();
for (SysMenu dept : menus)
{
tempList.add(dept.getMenuId());
}
for (Iterator<SysMenu> iterator = menus.iterator(); iterator.hasNext();)
{
SysMenu t = (SysMenu) iterator.next();
// 根据传入的某个父节点ID,遍历该父节点的所有子节点
if (t.getParentId() == 0)
SysMenu menu = (SysMenu) iterator.next();
// 如果是顶级节点, 遍历该父节点的所有子节点
if (!tempList.contains(menu.getParentId()))
{
recursionFn(menus, t);
returnList.add(t);
recursionFn(menus, menu);
returnList.add(menu);
}
}
if (returnList.isEmpty())
@ -406,13 +411,7 @@ public class SysMenuServiceImpl implements ISysMenuService
{
if (hasChild(list, tChild))
{
// 判断是否有子节点
Iterator<SysMenu> it = childList.iterator();
while (it.hasNext())
{
SysMenu n = (SysMenu) it.next();
recursionFn(list, n);
}
recursionFn(list, tChild);
}
}
}

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