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package class49 ;
import java.util.Arrays ;
public class Problem_0377_CombinationSumIV {
// 当前剩下的值是rest,
// nums中所有的值, 都可能作为分解rest的, 第一块! 全试一试
// nums, 无重复,都是正
// rest,
public static int ways ( int rest , int [ ] nums ) {
if ( rest < 0 ) {
return 0 ;
}
if ( rest = = 0 ) {
return 1 ;
}
int ways = 0 ;
for ( int num : nums ) {
ways + = ways ( rest - num , nums ) ;
}
return ways ;
}
public static int [ ] dp = new int [ 1001 ] ;
public static int combinationSum41 ( int [ ] nums , int target ) {
Arrays . fill ( dp , 0 , target + 1 , - 1 ) ;
return process1 ( nums , target ) ;
}
public static int process1 ( int [ ] nums , int rest ) {
if ( rest < 0 ) {
return 0 ;
}
if ( dp [ rest ] ! = - 1 ) {
return dp [ rest ] ;
}
int ans = 0 ;
if ( rest = = 0 ) {
ans = 1 ;
} else {
for ( int num : nums ) {
ans + = process1 ( nums , rest - num ) ;
}
}
dp [ rest ] = ans ;
return ans ;
}
// 剪枝 + 严格位置依赖的动态规划
public static int combinationSum42 ( int [ ] nums , int target ) {
Arrays . sort ( nums ) ;
int [ ] dp = new int [ target + 1 ] ;
dp [ 0 ] = 1 ;
for ( int rest = 1 ; rest < = target ; rest + + ) {
for ( int i = 0 ; i < nums . length & & nums [ i ] < = rest ; i + + ) {
dp [ rest ] + = dp [ rest - nums [ i ] ] ;
}
}
return dp [ target ] ;
}
}