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36 lines
1.0 KiB
36 lines
1.0 KiB
package class_2022_11_5_week;
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// 将一个给定字符串 s 根据给定的行数 numRows
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// 以从上往下、从左到右进行 Z 字形排列
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// 比如输入字符串为 "PAYPALISHIRING" 行数为 3 时，排列如下
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// P A H N
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// A P L S I I G
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// Y I R
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// 之后，你的输出需要从左往右逐行读取，产生出一个新的字符串
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// "PAHNAPLSIIGYIR"
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// 请你实现这个将字符串进行指定行数变换的函数
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// string convert(string s, int numRows)
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// 测试链接 : https://leetcode.cn/problems/zigzag-conversion/
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public class Code02_ZigZagConversion {
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public static String convert(String s, int row) {
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int n = s.length();
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if (row == 1 || row >= n) {
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return s;
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}
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int t = 2 * (row - 1);
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char[] ans = new char[n];
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int fill = 0;
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for (int i = 0; i < row; i++) {
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for (int j = i, nextColTop = t; j < n; j += t, nextColTop += t) {
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ans[fill++] = s.charAt(j);
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if (i >= 1 && i <= row - 2 && nextColTop - i < n) {
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ans[fill++] = s.charAt(nextColTop - i);
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}
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}
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}
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return String.valueOf(ans);
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}
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}
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