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package class33;
public class Problem_0238_ProductOfArrayExceptSelf {
public int[] productExceptSelf(int[] nums) {
int n = nums.length;
int[] ans = new int[n];
ans[0] = nums[0];
for (int i = 1; i < n; i++) {
ans[i] = ans[i - 1] * nums[i];
}
int right = 1;
for (int i = n - 1; i > 0; i--) {
ans[i] = ans[i - 1] * right;
right *= nums[i];
ans[0] = right;
return ans;
// 扩展 : 如果仅仅是不能用除号，把结果直接填在nums里呢？
// 解法：数一共几个0；每一个位得到结果就是，a / b，位运算替代 /，之前的课讲过（新手班）
