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package class24;
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import java.util.ArrayList;
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import java.util.List;
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public class Code04_Painting {
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// N * M的棋盘
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// 每种颜色的格子数必须相同的
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// 相邻格子染的颜色必须不同
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// 所有格子必须染色
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// 返回至少多少种颜色可以完成任务
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public static int minColors(int N, int M) {
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// 颜色数量是i
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for (int i = 2; i < N * M; i++) {
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int[][] matrix = new int[N][M];
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// 下面这一句可知,需要的最少颜色数i,一定是N*M的某个因子
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if ((N * M) % i == 0 && can(matrix, N, M, i)) {
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return i;
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}
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}
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return N * M;
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}
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// 在matrix上染色,返回只用pNum种颜色是否可以做到要求
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public static boolean can(int[][] matrix, int N, int M, int pNum) {
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int all = N * M;
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int every = all / pNum;
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ArrayList<Integer> rest = new ArrayList<>();
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rest.add(0);
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for (int i = 1; i <= pNum; i++) {
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rest.add(every);
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}
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return process(matrix, N, M, pNum, 0, 0, rest);
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}
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public static boolean process(int[][] matrix, int N, int M, int pNum, int row, int col, List<Integer> rest) {
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if (row == N) {
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return true;
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}
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if (col == M) {
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return process(matrix, N, M, pNum, row + 1, 0, rest);
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}
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int left = col == 0 ? 0 : matrix[row][col - 1];
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int up = row == 0 ? 0 : matrix[row - 1][col];
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for (int color = 1; color <= pNum; color++) {
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if (color != left && color != up && rest.get(color) > 0) {
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int count = rest.get(color);
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rest.set(color, count - 1);
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matrix[row][col] = color;
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if (process(matrix, N, M, pNum, row, col + 1, rest)) {
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return true;
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}
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rest.set(color, count);
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matrix[row][col] = 0;
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}
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}
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return false;
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}
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public static void main(String[] args) {
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// 根据代码16行的提示,打印出答案,看看是答案是哪个因子
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for (int N = 2; N < 10; N++) {
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for (int M = 2; M < 10; M++) {
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System.out.println("N = " + N);
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System.out.println("M = " + M);
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System.out.println("ans = " + minColors(N, M));
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System.out.println("===========");
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}
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}
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// 打印答案,分析可知,是N*M最小的质数因子,原因不明,也不重要
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// 反正打表法猜出来了
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}
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}
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