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package 第03期.mca_08;
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import java.util.ArrayList;
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// 设计一个包含一些单词的特殊词典,并能够通过前缀和后缀来检索单词。
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// 实现 WordFilter 类:
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// WordFilter(string[] words) 使用词典中的单词 words 初始化对象
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// f(string pref, string suff)
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// 返回词典中具有前缀 prefix 和后缀 suff 的单词的下标
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// 如果存在不止一个满足要求的下标,返回其中 最大的下标
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// 如果不存在这样的单词,返回 -1 。
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// 测试链接 : https://leetcode.cn/problems/prefix-and-suffix-search/
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public class Code03_PrefixAndSuffixSearch {
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// 提交以下这个类
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class WordFilter {
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class TrieNode {
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// new TrieNode[26]
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TrieNode[] nexts;
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// pass end 不要!这题不需要!
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// 有哪些字符串划过了这个节点,这些字符串的下标,记录!
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ArrayList<Integer> indies;
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public TrieNode() {
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nexts = new TrieNode[26];
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indies = new ArrayList<>();
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}
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}
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TrieNode preHead;
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TrieNode sufHead;
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// 初始化,有所有的字符串!
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public WordFilter(String[] words) {
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preHead = new TrieNode();
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sufHead = new TrieNode();
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for (int i = 0; i < words.length; i++) {
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// 所有字符串,i
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String word = words[i];
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TrieNode cur = preHead;
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for (int j = 0; j < word.length(); j++) {
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int path = word.charAt(j) - 'a';
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if (cur.nexts[path] == null) {
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cur.nexts[path] = new TrieNode();
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}
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cur = cur.nexts[path];
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cur.indies.add(i);
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}
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cur = sufHead;
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for (int j = word.length() - 1; j >= 0; j--) {
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int path = word.charAt(j) - 'a';
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if (cur.nexts[path] == null) {
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cur.nexts[path] = new TrieNode();
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}
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cur = cur.nexts[path];
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cur.indies.add(i);
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}
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}
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}
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// 给前缀 pref
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// 给后缀 suff
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public int f(String pref, String suff) {
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ArrayList<Integer> preList = null;
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TrieNode cur = preHead;
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for (int i = 0; i < pref.length() && cur != null; i++) {
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cur = cur.nexts[pref.charAt(i) - 'a'];
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}
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if(cur == null) {
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return -1;
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}
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if (cur != null) {
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preList = cur.indies;
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}
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ArrayList<Integer> sufList = null;
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cur = sufHead;
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for (int i = suff.length() - 1; i >= 0 && cur != null; i--) {
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cur = cur.nexts[suff.charAt(i) - 'a'];
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}
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if(cur == null) {
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return -1;
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}
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if (cur != null) {
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sufList = cur.indies;
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}
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ArrayList<Integer> small = preList.size() <= sufList.size() ? preList : sufList;
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ArrayList<Integer> big = small == preList ? sufList : preList;
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for (int i = small.size() - 1; i >= 0; i--) {
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if (bs(big, small.get(i))) {
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return small.get(i);
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}
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}
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return -1;
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}
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private boolean bs(ArrayList<Integer> sorted, int num) {
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int l = 0;
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int r = sorted.size() - 1;
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int m = 0;
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int midValue = 0;
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while (l <= r) {
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m = (l + r) / 2;
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midValue = sorted.get(m);
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if (midValue == num) {
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return true;
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} else if (midValue < num) {
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l = m + 1;
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} else {
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r = m - 1;
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}
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}
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return false;
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}
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}
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}
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