|
|
package class18;
|
|
|
|
|
|
// 牛客的测试链接:
|
|
|
// https://www.nowcoder.com/practice/7201cacf73e7495aa5f88b223bbbf6d1
|
|
|
// 不要提交包信息,把import底下的类名改成Main,提交下面的代码可以直接通过
|
|
|
// 因为测试平台会卡空间,所以把set换成了动态加和减的结构
|
|
|
// 请同学们务必参考如下代码中关于输入、输出的处理
|
|
|
// 这是输入输出处理效率很高的写法
|
|
|
import java.io.BufferedReader;
|
|
|
import java.io.IOException;
|
|
|
import java.io.InputStreamReader;
|
|
|
import java.io.OutputStreamWriter;
|
|
|
import java.io.PrintWriter;
|
|
|
import java.io.StreamTokenizer;
|
|
|
import java.util.Comparator;
|
|
|
import java.util.HashSet;
|
|
|
import java.util.PriorityQueue;
|
|
|
|
|
|
public class Code04_TopKSumCrossTwoArrays {
|
|
|
|
|
|
public static void main(String[] args) throws IOException {
|
|
|
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
|
|
|
StreamTokenizer in = new StreamTokenizer(br);
|
|
|
PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));
|
|
|
while (in.nextToken() != StreamTokenizer.TT_EOF) {
|
|
|
int N = (int) in.nval;
|
|
|
in.nextToken();
|
|
|
int K = (int) in.nval;
|
|
|
int[] arr1 = new int[N];
|
|
|
int[] arr2 = new int[N];
|
|
|
for (int i = 0; i < N; i++) {
|
|
|
in.nextToken();
|
|
|
arr1[i] = (int) in.nval;
|
|
|
}
|
|
|
for (int i = 0; i < N; i++) {
|
|
|
in.nextToken();
|
|
|
arr2[i] = (int) in.nval;
|
|
|
}
|
|
|
int[] topK = topKSum(arr1, arr2, K);
|
|
|
for (int i = 0; i < K; i++) {
|
|
|
out.print(topK[i] + " ");
|
|
|
}
|
|
|
out.println();
|
|
|
out.flush();
|
|
|
}
|
|
|
}
|
|
|
|
|
|
// 放入大根堆中的结构
|
|
|
public static class Node {
|
|
|
public int index1;// arr1中的位置
|
|
|
public int index2;// arr2中的位置
|
|
|
public int sum;// arr1[index1] + arr2[index2]的值
|
|
|
|
|
|
public Node(int i1, int i2, int s) {
|
|
|
index1 = i1;
|
|
|
index2 = i2;
|
|
|
sum = s;
|
|
|
}
|
|
|
}
|
|
|
|
|
|
// 生成大根堆的比较器
|
|
|
public static class MaxHeapComp implements Comparator<Node> {
|
|
|
@Override
|
|
|
public int compare(Node o1, Node o2) {
|
|
|
return o2.sum - o1.sum;
|
|
|
}
|
|
|
}
|
|
|
|
|
|
public static int[] topKSum(int[] arr1, int[] arr2, int topK) {
|
|
|
if (arr1 == null || arr2 == null || topK < 1) {
|
|
|
return null;
|
|
|
}
|
|
|
int N = arr1.length;
|
|
|
int M = arr2.length;
|
|
|
topK = Math.min(topK, N * M);
|
|
|
int[] res = new int[topK];
|
|
|
int resIndex = 0;
|
|
|
PriorityQueue<Node> maxHeap = new PriorityQueue<>(new MaxHeapComp());
|
|
|
HashSet<Long> set = new HashSet<>();
|
|
|
int i1 = N - 1;
|
|
|
int i2 = M - 1;
|
|
|
maxHeap.add(new Node(i1, i2, arr1[i1] + arr2[i2]));
|
|
|
set.add(x(i1, i2, M));
|
|
|
while (resIndex != topK) {
|
|
|
Node curNode = maxHeap.poll();
|
|
|
res[resIndex++] = curNode.sum;
|
|
|
i1 = curNode.index1;
|
|
|
i2 = curNode.index2;
|
|
|
set.remove(x(i1, i2, M));
|
|
|
if (i1 - 1 >= 0 && !set.contains(x(i1 - 1, i2, M))) {
|
|
|
set.add(x(i1 - 1, i2, M));
|
|
|
maxHeap.add(new Node(i1 - 1, i2, arr1[i1 - 1] + arr2[i2]));
|
|
|
}
|
|
|
if (i2 - 1 >= 0 && !set.contains(x(i1, i2 - 1, M))) {
|
|
|
set.add(x(i1, i2 - 1, M));
|
|
|
maxHeap.add(new Node(i1, i2 - 1, arr1[i1] + arr2[i2 - 1]));
|
|
|
}
|
|
|
}
|
|
|
return res;
|
|
|
}
|
|
|
|
|
|
public static long x(int i1, int i2, int M) {
|
|
|
return (long) i1 * (long) M + (long) i2;
|
|
|
}
|
|
|
|
|
|
}
|