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package class29;
public class Problem_0050_PowXN {
public static int pow(int a, int n) {
int ans = 1;
int t = a;
while (n != 0) {
if ((n & 1) != 0) {
ans *= t;
}
t *= t;
n >>= 1;
return ans;
// x的n次方,n可能是负数
public static double myPow(double x, int n) {
if (n == 0) {
return 1D;
int pow = Math.abs(n == Integer.MIN_VALUE ? n + 1 : n);
double t = x;
double ans = 1D;
while (pow != 0) {
if ((pow & 1) != 0) {
pow >>= 1;
t = t * t;
if (n == Integer.MIN_VALUE) {
ans *= x;
return n < 0 ? (1D / ans) : ans;