modify code

master
algorithmzuo 3 years ago
parent b12972232d
commit 049a6113b6

@ -0,0 +1,48 @@
package 03.mca_01;
public class Code01_Swap {
public static void main(String[] args) {
int a = 16;
int b = 603;
System.out.println(a);
System.out.println(b);
a = a ^ b;
b = a ^ b;
a = a ^ b;
System.out.println(a);
System.out.println(b);
int[] arr = { 3, 1, 100 };
int i = 0;
int j = 0;
arr[i] = arr[i] ^ arr[j];
arr[j] = arr[i] ^ arr[j];
arr[i] = arr[i] ^ arr[j];
System.out.println(arr[i] + " , " + arr[j]);
System.out.println(arr[0]);
System.out.println(arr[2]);
swap(arr, 0, 0);
System.out.println(arr[0]);
System.out.println(arr[2]);
}
public static void swap(int[] arr, int i, int j) {
// arr[0] = arr[0] ^ arr[0];
arr[i] = arr[i] ^ arr[j];
arr[j] = arr[i] ^ arr[j];
arr[i] = arr[i] ^ arr[j];
}
}

@ -0,0 +1,83 @@
package 03.mca_01;
public class Code02_EvenTimesOddTimes {
// arr中只有一种数出现奇数次
public static void printOddTimesNum1(int[] arr) {
int eor = 0;
for (int i = 0; i < arr.length; i++) {
eor ^= arr[i];
}
System.out.println(eor);
}
// arr中有两种数出现奇数次
public static void printOddTimesNum2(int[] arr) {
int eor = 0;
for (int i = 0; i < arr.length; i++) {
eor ^= arr[i];
}
// a 和 b是两种数
// eor != 0
// eor最右侧的1提取出来
// eor : 00110010110111000
// rightOne :00000000000001000
int rightOne = eor & (-eor); // 提取出最右的1
int onlyOne = 0; // eor'
for (int i = 0 ; i < arr.length;i++) {
// arr[1] = 111100011110000
// rightOne= 000000000010000
if ((arr[i] & rightOne) != 0) {
onlyOne ^= arr[i];
}
}
System.out.println(onlyOne + " " + (eor ^ onlyOne));
}
public static int bit1counts(int N) {
int count = 0;
// 011011010000
// 000000010000 1
// 011011000000
//
while(N != 0) {
int rightOne = N & ((~N) + 1);
count++;
N ^= rightOne;
// N -= rightOne
}
return count;
}
public static void main(String[] args) {
int a = 5;
int b = 7;
a = a ^ b;
b = a ^ b;
a = a ^ b;
System.out.println(a);
System.out.println(b);
int[] arr1 = { 3, 3, 2, 3, 1, 1, 1, 3, 1, 1, 1 };
printOddTimesNum1(arr1);
int[] arr2 = { 4, 3, 4, 2, 2, 2, 4, 1, 1, 1, 3, 3, 1, 1, 1, 4, 2, 2 };
printOddTimesNum2(arr2);
}
}

@ -0,0 +1,60 @@
package 03.mca_01;
public class Code03_BinarySearch {
public static boolean exist(int[] sortedArr, int num) {
if (sortedArr == null || sortedArr.length == 0) {
return false;
}
int L = 0;
int R = sortedArr.length - 1;
int mid = 0;
// L..R
while (L < R) { // L..R 至少两个数的时候
mid = L + ((R - L) >> 1);
if (sortedArr[mid] == num) {
return true;
} else if (sortedArr[mid] > num) {
R = mid - 1;
} else {
L = mid + 1;
}
}
return sortedArr[L] == num;
}
// 在arr上找满足>=value的最左位置
public static int nearest1(int[] sortedArr, int value) {
int L = 0;
int R = sortedArr.length - 1;
int index = -1; // 记录最左的对号
while (L <= R) { // 至少一个数的时候
int mid = L + ((R - L) >> 1);
if (sortedArr[mid] >= value) {
index = mid;
R = mid - 1;
} else {
L = mid + 1;
}
}
return index;
}
// 在arr上找满足<=value的最右位置
public static int nearest2(int[] sortedArr, int value) {
int L = 0;
int R = sortedArr.length - 1;
int index = -1; // 记录最右的对号
while (L <= R) {
int mid = L + ((R - L) >> 1);
if (sortedArr[mid] <= value) {
index = mid;
L = mid + 1;
} else {
R = mid - 1;
}
}
return index;
}
}

@ -0,0 +1,58 @@
package 03.mca_01;
import java.util.HashMap;
public class Code04_IsStepSum {
public static boolean isStepSum(int stepSum) {
int L = 0;
int R = stepSum;
int M = 0;
int cur = 0;
while (L <= R) {
M = L + ((R - L) >> 1);
cur = stepSum(M);
if (cur == stepSum) {
return true;
} else if (cur < stepSum) {
L = M + 1;
} else {
R = M - 1;
}
}
return false;
}
public static int stepSum(int num) {
int sum = 0;
while (num != 0) {
sum += num;
num /= 10;
}
return sum;
}
// for test
public static HashMap<Integer, Integer> generateStepSumNumberMap(int numMax) {
HashMap<Integer, Integer> map = new HashMap<>();
for (int i = 0; i <= numMax; i++) {
map.put(stepSum(i), i);
}
return map;
}
// for test
public static void main(String[] args) {
int max = 1000000;
int maxStepSum = stepSum(max);
HashMap<Integer, Integer> ans = generateStepSumNumberMap(max);
System.out.println("测试开始");
for (int i = 0; i <= maxStepSum; i++) {
if (isStepSum(i) ^ ans.containsKey(i)) {
System.out.println("出错了!");
}
}
System.out.println("测试结束");
}
}

@ -0,0 +1,35 @@
package 03.mca_01;
// leetcode 875题
public class Code05_KokoEatingBananas {
public static int minEatingSpeed(int[] piles, int h) {
int L = 1;
int R = 0;
for (int pile : piles) {
R = Math.max(R, pile);
}
int ans = 0;
int M = 0;
while (L <= R) {
M = L + ((R - L) >> 1);
if (hours(piles, M) <= h) {
ans = M;
R = M - 1;
} else {
L = M + 1;
}
}
return ans;
}
public static int hours(int[] piles, int speed) {
int ans = 0;
int offset = speed - 1;
for (int pile : piles) {
ans += (pile + offset) / speed;
}
return ans;
}
}

@ -0,0 +1,128 @@
package 03.mca_01;
import java.util.HashMap;
import java.util.HashSet;
import java.util.TreeMap;
public class Code06_HashMapAndSortedMap {
public static class Node {
public int value;
public Node(int v) {
value = v;
}
}
public static class Zuo {
public int value;
public Zuo(int v) {
value = v;
}
}
public static void main(String[] args) {
HashMap<Integer, String> test = new HashMap<>();
Integer a = 19000000;
Integer b = 19000000;
System.out.println(a == b);
test.put(a, "我是3");
System.out.println(test.containsKey(b));
Zuo z1 = new Zuo(1);
Zuo z2 = new Zuo(1);
HashMap<Zuo, String> test2 = new HashMap<>();
test2.put(z1, "我是z1");
System.out.println(test2.containsKey(z2));
// UnSortedMap
HashMap<Integer, String> map = new HashMap<>();
map.put(1000000, "我是1000000");
map.put(2, "我是2");
map.put(3, "我是3");
map.put(4, "我是4");
map.put(5, "我是5");
map.put(6, "我是6");
map.put(1000000, "我是1000001");
System.out.println(map.containsKey(1));
System.out.println(map.containsKey(10));
System.out.println(map.get(4));
System.out.println(map.get(10));
map.put(4, "他是4");
System.out.println(map.get(4));
map.remove(4);
System.out.println(map.get(4));
// key
HashSet<String> set = new HashSet<>();
set.add("abc");
set.contains("abc");
set.remove("abc");
// 哈希表增、删、改、查在使用时O1
System.out.println("=====================");
Integer c = 100000;
Integer d = 100000;
System.out.println(c.equals(d));
Integer e = 127; // - 128 ~ 127
Integer f = 127;
System.out.println(e == f);
HashMap<Node, String> map2 = new HashMap<>();
Node node1 = new Node(1);
Node node2 = node1;
map2.put(node1, "我是node1");
map2.put(node2, "我是node1");
System.out.println(map2.size());
System.out.println("======================");
// TreeMap 有序表:接口名
// 红黑树、avl、sb树、跳表
// O(logN)
System.out.println("有序表测试开始");
TreeMap<Integer, String> treeMap = new TreeMap<>();
treeMap.put(3, "我是3");
treeMap.put(4, "我是4");
treeMap.put(8, "我是8");
treeMap.put(5, "我是5");
treeMap.put(7, "我是7");
treeMap.put(1, "我是1");
treeMap.put(2, "我是2");
System.out.println(treeMap.containsKey(1));
System.out.println(treeMap.containsKey(10));
System.out.println(treeMap.get(4));
System.out.println(treeMap.get(10));
treeMap.put(4, "他是4");
System.out.println(treeMap.get(4));
// treeMap.remove(4);
System.out.println(treeMap.get(4));
System.out.println("新鲜:");
System.out.println(treeMap.firstKey());
System.out.println(treeMap.lastKey());
// <= 4
System.out.println(treeMap.floorKey(4));
// >= 4
System.out.println(treeMap.ceilingKey(4));
// O(logN)
}
}

@ -0,0 +1,155 @@
package 03.mca_01;
import java.util.Arrays;
import java.util.Comparator;
import java.util.PriorityQueue;
public class Code07_CoverMax {
public static int maxCover1(int[][] lines) {
int min = Integer.MAX_VALUE;
int max = Integer.MIN_VALUE;
for (int i = 0; i < lines.length; i++) {
min = Math.min(min, lines[i][0]);
max = Math.max(max, lines[i][1]);
}
int cover = 0;
for (double p = min + 0.5; p < max; p += 1) {
int cur = 0;
for (int i = 0; i < lines.length; i++) {
if (lines[i][0] < p && lines[i][1] > p) {
cur++;
}
}
cover = Math.max(cover, cur);
}
return cover;
}
public static int maxCover2(int[][] m) {
Line[] lines = new Line[m.length];
for (int i = 0; i < m.length; i++) {
lines[i] = new Line(m[i][0], m[i][1]);
}
Arrays.sort(lines, new StartComparator());
// 小根堆,每一条线段的结尾数值,使用默认的
PriorityQueue<Integer> heap = new PriorityQueue<>();
int max = 0;
for (int i = 0; i < lines.length; i++) {
// lines[i] -> cur 在黑盒中,把<=cur.start 东西都弹出
while (!heap.isEmpty() && heap.peek() <= lines[i].start) {
heap.poll();
}
heap.add(lines[i].end);
max = Math.max(max, heap.size());
}
return max;
}
public static class Line {
public int start;
public int end;
public Line(int s, int e) {
start = s;
end = e;
}
}
public static class EndComparator implements Comparator<Line> {
@Override
public int compare(Line o1, Line o2) {
return o1.end - o2.end;
}
}
// 和maxCover2过程是一样的
// 只是代码更短
// 不使用类定义的写法
public static int maxCover3(int[][] m) {
// m是二维数组可以认为m内部是一个一个的一维数组
// 每一个一维数组就是一个对象,也就是线段
// 如下的code就是根据每一个线段的开始位置排序
// 比如, m = { {5,7}, {1,4}, {2,6} } 跑完如下的code之后变成{ {1,4}, {2,6}, {5,7} }
Arrays.sort(m, (a, b) -> (a[0] - b[0]));
// 准备好小根堆,和课堂的说法一样
PriorityQueue<Integer> heap = new PriorityQueue<>();
int max = 0;
for (int[] line : m) {
while (!heap.isEmpty() && heap.peek() <= line[0]) {
heap.poll();
}
heap.add(line[1]);
max = Math.max(max, heap.size());
}
return max;
}
// for test
public static int[][] generateLines(int N, int L, int R) {
int size = (int) (Math.random() * N) + 1;
int[][] ans = new int[size][2];
for (int i = 0; i < size; i++) {
int a = L + (int) (Math.random() * (R - L + 1));
int b = L + (int) (Math.random() * (R - L + 1));
if (a == b) {
b = a + 1;
}
ans[i][0] = Math.min(a, b);
ans[i][1] = Math.max(a, b);
}
return ans;
}
public static class StartComparator implements Comparator<Line> {
@Override
public int compare(Line o1, Line o2) {
return o1.start - o2.start;
}
}
public static void main(String[] args) {
Line l1 = new Line(4, 9);
Line l2 = new Line(1, 4);
Line l3 = new Line(7, 15);
Line l4 = new Line(2, 4);
Line l5 = new Line(4, 6);
Line l6 = new Line(3, 7);
// 底层堆结构heap
PriorityQueue<Line> heap = new PriorityQueue<>(new StartComparator());
heap.add(l1);
heap.add(l2);
heap.add(l3);
heap.add(l4);
heap.add(l5);
heap.add(l6);
while (!heap.isEmpty()) {
Line cur = heap.poll();
System.out.println(cur.start + "," + cur.end);
}
System.out.println("test begin");
int N = 100;
int L = 0;
int R = 200;
int testTimes = 200000;
for (int i = 0; i < testTimes; i++) {
int[][] lines = generateLines(N, L, R);
int ans1 = maxCover1(lines);
int ans2 = maxCover2(lines);
int ans3 = maxCover3(lines);
if (ans1 != ans2 || ans1 != ans3) {
System.out.println("Oops!");
}
}
System.out.println("test end");
}
}

@ -0,0 +1,79 @@
package 03.mca_01;
import java.util.PriorityQueue;
public class Code08_LessMoneySplitGold {
// 纯暴力!
public static int lessMoney1(int[] arr) {
if (arr == null || arr.length == 0) {
return 0;
}
return process(arr, 0);
}
// 等待合并的数都在arr里pre之前的合并行为产生了多少总代价
// arr中只剩一个数字的时候停止合并返回最小的总代价
public static int process(int[] arr, int pre) {
if (arr.length == 1) {
return pre;
}
int ans = Integer.MAX_VALUE;
for (int i = 0; i < arr.length; i++) {
for (int j = i + 1; j < arr.length; j++) {
ans = Math.min(ans, process(copyAndMergeTwo(arr, i, j), pre + arr[i] + arr[j]));
}
}
return ans;
}
public static int[] copyAndMergeTwo(int[] arr, int i, int j) {
int[] ans = new int[arr.length - 1];
int ansi = 0;
for (int arri = 0; arri < arr.length; arri++) {
if (arri != i && arri != j) {
ans[ansi++] = arr[arri];
}
}
ans[ansi] = arr[i] + arr[j];
return ans;
}
public static int lessMoney2(int[] arr) {
PriorityQueue<Integer> pQ = new PriorityQueue<>();
for (int i = 0; i < arr.length; i++) {
pQ.add(arr[i]);
}
int sum = 0;
int cur = 0;
while (pQ.size() > 1) {
cur = pQ.poll() + pQ.poll();
sum += cur;
pQ.add(cur);
}
return sum;
}
// for test
public static int[] generateRandomArray(int maxSize, int maxValue) {
int[] arr = new int[(int) ((maxSize + 1) * Math.random())];
for (int i = 0; i < arr.length; i++) {
arr[i] = (int) (Math.random() * (maxValue + 1));
}
return arr;
}
public static void main(String[] args) {
int testTime = 100000;
int maxSize = 6;
int maxValue = 1000;
for (int i = 0; i < testTime; i++) {
int[] arr = generateRandomArray(maxSize, maxValue);
if (lessMoney1(arr) != lessMoney2(arr)) {
System.out.println("Oops!");
}
}
System.out.println("finish!");
}
}

@ -0,0 +1,62 @@
package 03.mca_02;
// 测试链接https://leetcode.com/problems/add-two-numbers/
public class Code01_AddTwoNumbers {
// 不要提交这个类
public static class ListNode {
public int val;
public ListNode next;
public ListNode(int val) {
this.val = val;
}
public ListNode(int val, ListNode next) {
this.val = val;
this.next = next;
}
}
public static ListNode addTwoNumbers(ListNode head1, ListNode head2) {
int len1 = listLength(head1);
int len2 = listLength(head2);
ListNode l = len1 >= len2 ? head1 : head2;
ListNode s = l == head1 ? head2 : head1;
ListNode curL = l;
ListNode curS = s;
ListNode last = curL;
int carry = 0;
int curNum = 0;
while (curS != null) {
curNum = curL.val + curS.val + carry;
curL.val = (curNum % 10);
carry = curNum / 10;
last = curL;
curL = curL.next;
curS = curS.next;
}
while (curL != null) {
curNum = curL.val + carry;
curL.val = (curNum % 10);
carry = curNum / 10;
last = curL;
curL = curL.next;
}
if (carry != 0) {
last.next = new ListNode(1);
}
return l;
}
// 求链表长度
public static int listLength(ListNode head) {
int len = 0;
while (head != null) {
len++;
head = head.next;
}
return len;
}
}

@ -0,0 +1,204 @@
package 03.mca_02;
import java.util.Stack;
public class Code02_IsPalindromeList {
public static class Node {
public int value;
public Node next;
public Node(int data) {
this.value = data;
}
}
// need n extra space
public static boolean isPalindrome1(Node head) {
Stack<Node> stack = new Stack<Node>();
Node cur = head;
while (cur != null) {
stack.push(cur);
cur = cur.next;
}
while (head != null) {
if (head.value != stack.pop().value) {
return false;
}
head = head.next;
}
return true;
}
// need n/2 extra space
public static boolean isPalindrome2(Node head) {
if (head == null || head.next == null) {
return true;
}
Node right = head.next;
Node cur = head;
while (cur.next != null && cur.next.next != null) {
right = right.next;
cur = cur.next.next;
}
Stack<Node> stack = new Stack<Node>();
while (right != null) {
stack.push(right);
right = right.next;
}
while (!stack.isEmpty()) {
if (head.value != stack.pop().value) {
return false;
}
head = head.next;
}
return true;
}
// need O(1) extra space
public static boolean isPalindrome3(Node head) {
if (head == null || head.next == null) {
return true;
}
Node n1 = head;
Node n2 = head;
while (n2.next != null && n2.next.next != null) { // find mid node
n1 = n1.next; // n1 -> mid
n2 = n2.next.next; // n2 -> end
}
// n1 中点
n2 = n1.next; // n2 -> right part first node
n1.next = null; // mid.next -> null
Node n3 = null;
while (n2 != null) { // right part convert
n3 = n2.next; // n3 -> save next node
n2.next = n1; // next of right node convert
n1 = n2; // n1 move
n2 = n3; // n2 move
}
n3 = n1; // n3 -> save last node
n2 = head;// n2 -> left first node
boolean res = true;
while (n1 != null && n2 != null) { // check palindrome
if (n1.value != n2.value) {
res = false;
break;
}
n1 = n1.next; // left to mid
n2 = n2.next; // right to mid
}
n1 = n3.next;
n3.next = null;
while (n1 != null) { // recover list
n2 = n1.next;
n1.next = n3;
n3 = n1;
n1 = n2;
}
return res;
}
public static void printLinkedList(Node node) {
System.out.print("Linked List: ");
while (node != null) {
System.out.print(node.value + " ");
node = node.next;
}
System.out.println();
}
public static void main(String[] args) {
Node head = null;
printLinkedList(head);
System.out.print(isPalindrome1(head) + " | ");
System.out.print(isPalindrome2(head) + " | ");
System.out.println(isPalindrome3(head) + " | ");
printLinkedList(head);
System.out.println("=========================");
head = new Node(1);
printLinkedList(head);
System.out.print(isPalindrome1(head) + " | ");
System.out.print(isPalindrome2(head) + " | ");
System.out.println(isPalindrome3(head) + " | ");
printLinkedList(head);
System.out.println("=========================");
head = new Node(1);
head.next = new Node(2);
printLinkedList(head);
System.out.print(isPalindrome1(head) + " | ");
System.out.print(isPalindrome2(head) + " | ");
System.out.println(isPalindrome3(head) + " | ");
printLinkedList(head);
System.out.println("=========================");
head = new Node(1);
head.next = new Node(1);
printLinkedList(head);
System.out.print(isPalindrome1(head) + " | ");
System.out.print(isPalindrome2(head) + " | ");
System.out.println(isPalindrome3(head) + " | ");
printLinkedList(head);
System.out.println("=========================");
head = new Node(1);
head.next = new Node(2);
head.next.next = new Node(3);
printLinkedList(head);
System.out.print(isPalindrome1(head) + " | ");
System.out.print(isPalindrome2(head) + " | ");
System.out.println(isPalindrome3(head) + " | ");
printLinkedList(head);
System.out.println("=========================");
head = new Node(1);
head.next = new Node(2);
head.next.next = new Node(1);
printLinkedList(head);
System.out.print(isPalindrome1(head) + " | ");
System.out.print(isPalindrome2(head) + " | ");
System.out.println(isPalindrome3(head) + " | ");
printLinkedList(head);
System.out.println("=========================");
head = new Node(1);
head.next = new Node(2);
head.next.next = new Node(3);
head.next.next.next = new Node(1);
printLinkedList(head);
System.out.print(isPalindrome1(head) + " | ");
System.out.print(isPalindrome2(head) + " | ");
System.out.println(isPalindrome3(head) + " | ");
printLinkedList(head);
System.out.println("=========================");
head = new Node(1);
head.next = new Node(2);
head.next.next = new Node(2);
head.next.next.next = new Node(1);
printLinkedList(head);
System.out.print(isPalindrome1(head) + " | ");
System.out.print(isPalindrome2(head) + " | ");
System.out.println(isPalindrome3(head) + " | ");
printLinkedList(head);
System.out.println("=========================");
head = new Node(1);
head.next = new Node(2);
head.next.next = new Node(3);
head.next.next.next = new Node(2);
head.next.next.next.next = new Node(1);
printLinkedList(head);
System.out.print(isPalindrome1(head) + " | ");
System.out.print(isPalindrome2(head) + " | ");
System.out.println(isPalindrome3(head) + " | ");
printLinkedList(head);
System.out.println("=========================");
}
}

@ -0,0 +1,138 @@
package 03.mca_02;
public class Code03_SmallerEqualBigger {
public static class Node {
public int value;
public Node next;
public Node(int data) {
this.value = data;
}
}
public static Node listPartition1(Node head, int pivot) {
if (head == null) {
return head;
}
Node cur = head;
int i = 0;
while (cur != null) {
i++;
cur = cur.next;
}
Node[] nodeArr = new Node[i];
i = 0;
cur = head;
for (i = 0; i != nodeArr.length; i++) {
nodeArr[i] = cur;
cur = cur.next;
}
arrPartition(nodeArr, pivot);
for (i = 1; i != nodeArr.length; i++) {
nodeArr[i - 1].next = nodeArr[i];
}
nodeArr[i - 1].next = null;
return nodeArr[0];
}
public static void arrPartition(Node[] nodeArr, int pivot) {
int small = -1;
int big = nodeArr.length;
int index = 0;
while (index != big) {
if (nodeArr[index].value < pivot) {
swap(nodeArr, ++small, index++);
} else if (nodeArr[index].value == pivot) {
index++;
} else {
swap(nodeArr, --big, index);
}
}
}
public static void swap(Node[] nodeArr, int a, int b) {
Node tmp = nodeArr[a];
nodeArr[a] = nodeArr[b];
nodeArr[b] = tmp;
}
public static Node listPartition2(Node head, int pivot) {
Node sH = null; // small head
Node sT = null; // small tail
Node eH = null; // equal head
Node eT = null; // equal tail
Node mH = null; // big head
Node mT = null; // big tail
Node next = null; // save next node
// every node distributed to three lists
while (head != null) {
next = head.next;
head.next = null;
if (head.value < pivot) {
if (sH == null) {
sH = head;
sT = head;
} else {
sT.next = head;
sT = head;
}
} else if (head.value == pivot) {
if (eH == null) {
eH = head;
eT = head;
} else {
eT.next = head;
eT = head;
}
} else {
if (mH == null) {
mH = head;
mT = head;
} else {
mT.next = head;
mT = head;
}
}
head = next;
}
// 小于区域的尾巴,连等于区域的头,等于区域的尾巴连大于区域的头
if (sT != null) { // 如果有小于区域
sT.next = eH;
eT = eT == null ? sT : eT; // 下一步谁去连大于区域的头谁就变成eT
}
// 下一步一定是需要用eT 去接 大于区域的头
// 有等于区域eT -> 等于区域的尾结点
// 无等于区域eT -> 小于区域的尾结点
// eT 尽量不为空的尾巴节点
if (eT != null) { // 如果小于区域和等于区域,不是都没有
eT.next = mH;
}
return sH != null ? sH : (eH != null ? eH : mH);
}
public static void printLinkedList(Node node) {
System.out.print("Linked List: ");
while (node != null) {
System.out.print(node.value + " ");
node = node.next;
}
System.out.println();
}
public static void main(String[] args) {
Node head1 = new Node(7);
head1.next = new Node(9);
head1.next.next = new Node(1);
head1.next.next.next = new Node(8);
head1.next.next.next.next = new Node(5);
head1.next.next.next.next.next = new Node(2);
head1.next.next.next.next.next.next = new Node(5);
printLinkedList(head1);
// head1 = listPartition1(head1, 4);
head1 = listPartition2(head1, 5);
printLinkedList(head1);
}
}

@ -0,0 +1,79 @@
package 03.mca_02;
import java.util.HashMap;
// 测试链接 : https://leetcode.com/problems/copy-list-with-random-pointer/
public class Code04_CopyListWithRandom {
public static class Node {
int val;
Node next;
Node random;
public Node(int val) {
this.val = val;
this.next = null;
this.random = null;
}
}
public static Node copyRandomList1(Node head) {
// key 老节点
// value 新节点
HashMap<Node, Node> map = new HashMap<Node, Node>();
Node cur = head;
while (cur != null) {
map.put(cur, new Node(cur.val));
cur = cur.next;
}
cur = head;
while (cur != null) {
// cur 老
// map.get(cur) 新
// 新.next -> cur.next克隆节点找到
map.get(cur).next = map.get(cur.next);
map.get(cur).random = map.get(cur.random);
cur = cur.next;
}
return map.get(head);
}
public static Node copyRandomList2(Node head) {
if (head == null) {
return null;
}
Node cur = head;
Node next = null;
// 1 -> 2 -> 3 -> null
// 1 -> 1' -> 2 -> 2' -> 3 -> 3'
while (cur != null) {
next = cur.next;
cur.next = new Node(cur.val);
cur.next.next = next;
cur = next;
}
cur = head;
Node copy = null;
// 1 1' 2 2' 3 3'
// 依次设置 1' 2' 3' random指针
while (cur != null) {
next = cur.next.next;
copy = cur.next;
copy.random = cur.random != null ? cur.random.next : null;
cur = next;
}
Node res = head.next;
cur = head;
// 老 新 混在一起next方向上random正确
// next方向上把新老链表分离
while (cur != null) {
next = cur.next.next;
copy = cur.next;
cur.next = next;
copy.next = next != null ? next.next : null;
cur = next;
}
return res;
}
}

@ -0,0 +1,59 @@
package 03.mca_02;
// 测试链接https://leetcode.com/problems/reverse-nodes-in-k-group/
public class Code05_ReverseNodesInKGroup {
// 不要提交这个类
public static class ListNode {
public int val;
public ListNode next;
}
public static ListNode reverseKGroup(ListNode head, int k) {
ListNode start = head;
ListNode end = getKGroupEnd(start, k);
if (end == null) {
return head;
}
// 第一组凑齐了!
head = end;
reverse(start, end);
// 上一组的结尾节点
ListNode lastEnd = start;
while (lastEnd.next != null) {
start = lastEnd.next;
end = getKGroupEnd(start, k);
if (end == null) {
return head;
}
reverse(start, end);
lastEnd.next = end;
lastEnd = start;
}
return head;
}
public static ListNode getKGroupEnd(ListNode start, int k) {
while (--k != 0 && start != null) {
start = start.next;
}
return start;
}
public static void reverse(ListNode start, ListNode end) {
end = end.next;
ListNode pre = null;
ListNode cur = start;
ListNode next = null;
while (cur != end) {
next = cur.next;
cur.next = pre;
pre = cur;
cur = next;
}
start.next = end;
}
}

@ -0,0 +1,52 @@
package 03.mca_02;
import java.util.Comparator;
import java.util.PriorityQueue;
// 测试链接https://leetcode.com/problems/merge-k-sorted-lists/
public class Code06_MergeKSortedLists {
public static class ListNode {
public int val;
public ListNode next;
}
public static class ListNodeComparator implements Comparator<ListNode> {
@Override
public int compare(ListNode o1, ListNode o2) {
return o1.val - o2.val;
}
}
public static ListNode mergeKLists(ListNode[] lists) {
if (lists == null) {
return null;
}
PriorityQueue<ListNode> heap = new PriorityQueue<>(new ListNodeComparator());
for (int i = 0; i < lists.length; i++) {
if (lists[i] != null) {
heap.add(lists[i]);
}
}
if (heap.isEmpty()) {
return null;
}
ListNode head = heap.poll();
ListNode pre = head;
if (pre.next != null) {
heap.add(pre.next);
}
while (!heap.isEmpty()) {
ListNode cur = heap.poll();
pre.next = cur;
pre = cur;
if (cur.next != null) {
heap.add(cur.next);
}
}
return head;
}
}

@ -0,0 +1,170 @@
package 03.mca_02;
public class Code07_FindFirstIntersectNode {
public static class Node {
public int value;
public Node next;
public Node(int data) {
this.value = data;
}
}
public static Node getIntersectNode(Node head1, Node head2) {
if (head1 == null || head2 == null) {
return null;
}
Node loop1 = getLoopNode(head1);
Node loop2 = getLoopNode(head2);
if (loop1 == null && loop2 == null) {
return noLoop(head1, head2);
}
if (loop1 != null && loop2 != null) {
return bothLoop(head1, loop1, head2, loop2);
}
return null;
}
// 找到链表第一个入环节点如果无环返回null
public static Node getLoopNode(Node head) {
if (head == null || head.next == null || head.next.next == null) {
return null;
}
// n1 慢 n2 快
Node slow = head.next; // n1 -> slow
Node fast = head.next.next; // n2 -> fast
while (slow != fast) {
if (fast.next == null || fast.next.next == null) {
return null;
}
fast = fast.next.next;
slow = slow.next;
}
// slow fast 相遇
fast = head; // n2 -> walk again from head
while (slow != fast) {
slow = slow.next;
fast = fast.next;
}
return slow;
}
// 如果两个链表都无环返回第一个相交节点如果不想交返回null
public static Node noLoop(Node head1, Node head2) {
if (head1 == null || head2 == null) {
return null;
}
Node cur1 = head1;
Node cur2 = head2;
int n = 0;
while (cur1.next != null) {
n++;
cur1 = cur1.next;
}
while (cur2.next != null) {
n--;
cur2 = cur2.next;
}
if (cur1 != cur2) {
return null;
}
// n : 链表1长度减去链表2长度的值
cur1 = n > 0 ? head1 : head2; // 谁长谁的头变成cur1
cur2 = cur1 == head1 ? head2 : head1; // 谁短谁的头变成cur2
n = Math.abs(n);
while (n != 0) {
n--;
cur1 = cur1.next;
}
while (cur1 != cur2) {
cur1 = cur1.next;
cur2 = cur2.next;
}
return cur1;
}
// 两个有环链表返回第一个相交节点如果不想交返回null
public static Node bothLoop(Node head1, Node loop1, Node head2, Node loop2) {
Node cur1 = null;
Node cur2 = null;
if (loop1 == loop2) {
cur1 = head1;
cur2 = head2;
int n = 0;
while (cur1 != loop1) {
n++;
cur1 = cur1.next;
}
while (cur2 != loop2) {
n--;
cur2 = cur2.next;
}
cur1 = n > 0 ? head1 : head2;
cur2 = cur1 == head1 ? head2 : head1;
n = Math.abs(n);
while (n != 0) {
n--;
cur1 = cur1.next;
}
while (cur1 != cur2) {
cur1 = cur1.next;
cur2 = cur2.next;
}
return cur1;
} else {
cur1 = loop1.next;
while (cur1 != loop1) {
if (cur1 == loop2) {
return loop1;
}
cur1 = cur1.next;
}
return null;
}
}
public static void main(String[] args) {
// 1->2->3->4->5->6->7->null
Node head1 = new Node(1);
head1.next = new Node(2);
head1.next.next = new Node(3);
head1.next.next.next = new Node(4);
head1.next.next.next.next = new Node(5);
head1.next.next.next.next.next = new Node(6);
head1.next.next.next.next.next.next = new Node(7);
// 0->9->8->6->7->null
Node head2 = new Node(0);
head2.next = new Node(9);
head2.next.next = new Node(8);
head2.next.next.next = head1.next.next.next.next.next; // 8->6
System.out.println(getIntersectNode(head1, head2).value);
// 1->2->3->4->5->6->7->4...
head1 = new Node(1);
head1.next = new Node(2);
head1.next.next = new Node(3);
head1.next.next.next = new Node(4);
head1.next.next.next.next = new Node(5);
head1.next.next.next.next.next = new Node(6);
head1.next.next.next.next.next.next = new Node(7);
head1.next.next.next.next.next.next = head1.next.next.next; // 7->4
// 0->9->8->2...
head2 = new Node(0);
head2.next = new Node(9);
head2.next.next = new Node(8);
head2.next.next.next = head1.next; // 8->2
System.out.println(getIntersectNode(head1, head2).value);
// 0->9->8->6->4->5->6..
head2 = new Node(0);
head2.next = new Node(9);
head2.next.next = new Node(8);
head2.next.next.next = head1.next.next.next.next.next; // 8->6
System.out.println(getIntersectNode(head1, head2).value);
}
}
Loading…
Cancel
Save