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package class15;
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import java.util.ArrayList;
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import java.util.HashMap;
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import java.util.List;
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import java.util.Stack;
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// 本题为leetcode原题
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// 测试链接:https://leetcode.com/problems/number-of-islands/
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// 所有方法都可以直接通过
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public class Code02_NumberOfIslands {
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public static int numIslands3(char[][] board) {
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int islands = 0;
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for (int i = 0; i < board.length; i++) {
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for (int j = 0; j < board[0].length; j++) {
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if (board[i][j] == '1') {
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islands++;
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infect(board, i, j);
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}
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}
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}
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return islands;
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}
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// 从(i,j)这个位置出发,把所有练成一片的'1'字符,变成0
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public static void infect(char[][] board, int i, int j) {
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if (i < 0 || i == board.length || j < 0 || j == board[0].length || board[i][j] != '1') {
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return;
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}
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board[i][j] = 0;
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infect(board, i - 1, j);
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infect(board, i + 1, j);
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infect(board, i, j - 1);
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infect(board, i, j + 1);
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}
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public static int numIslands1(char[][] board) {
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int row = board.length;
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int col = board[0].length;
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Dot[][] dots = new Dot[row][col];
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List<Dot> dotList = new ArrayList<>();
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for (int i = 0; i < row; i++) {
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for (int j = 0; j < col; j++) {
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if (board[i][j] == '1') {
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dots[i][j] = new Dot();
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dotList.add(dots[i][j]);
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}
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}
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}
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UnionFind1<Dot> uf = new UnionFind1<>(dotList);
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for (int j = 1; j < col; j++) {
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// (0,j) (0,0)跳过了 (0,1) (0,2) (0,3)
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if (board[0][j - 1] == '1' && board[0][j] == '1') {
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uf.union(dots[0][j - 1], dots[0][j]);
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}
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}
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for (int i = 1; i < row; i++) {
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if (board[i - 1][0] == '1' && board[i][0] == '1') {
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uf.union(dots[i - 1][0], dots[i][0]);
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}
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}
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for (int i = 1; i < row; i++) {
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for (int j = 1; j < col; j++) {
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if (board[i][j] == '1') {
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if (board[i][j - 1] == '1') {
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uf.union(dots[i][j - 1], dots[i][j]);
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}
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if (board[i - 1][j] == '1') {
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uf.union(dots[i - 1][j], dots[i][j]);
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}
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}
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}
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}
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return uf.sets();
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}
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public static class Dot {
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}
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public static class Node<V> {
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V value;
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public Node(V v) {
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value = v;
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}
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}
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public static class UnionFind1<V> {
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public HashMap<V, Node<V>> nodes;
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public HashMap<Node<V>, Node<V>> parents;
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public HashMap<Node<V>, Integer> sizeMap;
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public UnionFind1(List<V> values) {
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nodes = new HashMap<>();
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parents = new HashMap<>();
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sizeMap = new HashMap<>();
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for (V cur : values) {
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Node<V> node = new Node<>(cur);
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nodes.put(cur, node);
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parents.put(node, node);
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sizeMap.put(node, 1);
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}
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}
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public Node<V> findFather(Node<V> cur) {
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Stack<Node<V>> path = new Stack<>();
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while (cur != parents.get(cur)) {
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path.push(cur);
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cur = parents.get(cur);
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}
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while (!path.isEmpty()) {
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parents.put(path.pop(), cur);
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}
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return cur;
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}
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public void union(V a, V b) {
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Node<V> aHead = findFather(nodes.get(a));
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Node<V> bHead = findFather(nodes.get(b));
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if (aHead != bHead) {
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int aSetSize = sizeMap.get(aHead);
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int bSetSize = sizeMap.get(bHead);
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Node<V> big = aSetSize >= bSetSize ? aHead : bHead;
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Node<V> small = big == aHead ? bHead : aHead;
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parents.put(small, big);
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sizeMap.put(big, aSetSize + bSetSize);
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sizeMap.remove(small);
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}
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}
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public int sets() {
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return sizeMap.size();
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}
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}
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public static int numIslands2(char[][] board) {
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int row = board.length;
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int col = board[0].length;
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UnionFind2 uf = new UnionFind2(board);
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for (int j = 1; j < col; j++) {
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if (board[0][j - 1] == '1' && board[0][j] == '1') {
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uf.union(0, j - 1, 0, j);
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}
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}
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for (int i = 1; i < row; i++) {
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if (board[i - 1][0] == '1' && board[i][0] == '1') {
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uf.union(i - 1, 0, i, 0);
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}
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}
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for (int i = 1; i < row; i++) {
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for (int j = 1; j < col; j++) {
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if (board[i][j] == '1') {
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if (board[i][j - 1] == '1') {
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uf.union(i, j - 1, i, j);
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}
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if (board[i - 1][j] == '1') {
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uf.union(i - 1, j, i, j);
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}
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}
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}
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}
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return uf.sets();
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}
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public static class UnionFind2 {
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private int[] parent;
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private int[] size;
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private int[] help;
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private int col;
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private int sets;
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public UnionFind2(char[][] board) {
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col = board[0].length;
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sets = 0;
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int row = board.length;
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int len = row * col;
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parent = new int[len];
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size = new int[len];
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help = new int[len];
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for (int r = 0; r < row; r++) {
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for (int c = 0; c < col; c++) {
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if (board[r][c] == '1') {
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int i = index(r, c);
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parent[i] = i;
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size[i] = 1;
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sets++;
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}
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}
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}
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}
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// (r,c) -> i
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private int index(int r, int c) {
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return r * col + c;
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}
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// 原始位置 -> 下标
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private int find(int i) {
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int hi = 0;
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while (i != parent[i]) {
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help[hi++] = i;
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i = parent[i];
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}
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for (hi--; hi >= 0; hi--) {
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parent[help[hi]] = i;
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}
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return i;
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}
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public void union(int r1, int c1, int r2, int c2) {
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int i1 = index(r1, c1);
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int i2 = index(r2, c2);
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int f1 = find(i1);
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int f2 = find(i2);
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if (f1 != f2) {
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if (size[f1] >= size[f2]) {
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size[f1] += size[f2];
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parent[f2] = f1;
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} else {
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size[f2] += size[f1];
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parent[f1] = f2;
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}
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sets--;
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}
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}
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public int sets() {
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return sets;
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}
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}
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// 为了测试
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public static char[][] generateRandomMatrix(int row, int col) {
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char[][] board = new char[row][col];
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for (int i = 0; i < row; i++) {
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for (int j = 0; j < col; j++) {
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board[i][j] = Math.random() < 0.5 ? '1' : '0';
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}
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}
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return board;
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}
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// 为了测试
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public static char[][] copy(char[][] board) {
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int row = board.length;
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int col = board[0].length;
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char[][] ans = new char[row][col];
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for (int i = 0; i < row; i++) {
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for (int j = 0; j < col; j++) {
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ans[i][j] = board[i][j];
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}
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}
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return ans;
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}
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// 为了测试
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public static void main(String[] args) {
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int row = 0;
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int col = 0;
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char[][] board1 = null;
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char[][] board2 = null;
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char[][] board3 = null;
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long start = 0;
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long end = 0;
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row = 1000;
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col = 1000;
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board1 = generateRandomMatrix(row, col);
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board2 = copy(board1);
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board3 = copy(board1);
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System.out.println("感染方法、并查集(map实现)、并查集(数组实现)的运行结果和运行时间");
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System.out.println("随机生成的二维矩阵规模 : " + row + " * " + col);
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start = System.currentTimeMillis();
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System.out.println("感染方法的运行结果: " + numIslands3(board1));
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end = System.currentTimeMillis();
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System.out.println("感染方法的运行时间: " + (end - start) + " ms");
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start = System.currentTimeMillis();
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System.out.println("并查集(map实现)的运行结果: " + numIslands1(board2));
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end = System.currentTimeMillis();
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System.out.println("并查集(map实现)的运行时间: " + (end - start) + " ms");
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start = System.currentTimeMillis();
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System.out.println("并查集(数组实现)的运行结果: " + numIslands2(board3));
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end = System.currentTimeMillis();
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System.out.println("并查集(数组实现)的运行时间: " + (end - start) + " ms");
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System.out.println();
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row = 10000;
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col = 10000;
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board1 = generateRandomMatrix(row, col);
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board3 = copy(board1);
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System.out.println("感染方法、并查集(数组实现)的运行结果和运行时间");
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System.out.println("随机生成的二维矩阵规模 : " + row + " * " + col);
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start = System.currentTimeMillis();
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System.out.println("感染方法的运行结果: " + numIslands3(board1));
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end = System.currentTimeMillis();
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System.out.println("感染方法的运行时间: " + (end - start) + " ms");
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start = System.currentTimeMillis();
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System.out.println("并查集(数组实现)的运行结果: " + numIslands2(board3));
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end = System.currentTimeMillis();
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System.out.println("并查集(数组实现)的运行时间: " + (end - start) + " ms");
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}
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}
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