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package class05;
// 如果一个节点X它左树结构和右树结构完全一样那么我们说以X为头的子树是相等子树
// 给定一棵二叉树的头节点head返回head整棵树上有多少棵相等子树
public class Code02_LeftRightSameTreeNumber {
public static class Node {
public int value;
public Node left;
public Node right;
public Node(int v) {
value = v;
}
}
// 时间复杂度O(N * logN)
public static int sameNumber1(Node head) {
if (head == null) {
return 0;
}
return sameNumber1(head.left) + sameNumber1(head.right) + (same(head.left, head.right) ? 1 : 0);
}
public static boolean same(Node h1, Node h2) {
if (h1 == null ^ h2 == null) {
return false;
}
if (h1 == null && h2 == null) {
return true;
}
// 两个都不为空
return h1.value == h2.value && same(h1.left, h2.left) && same(h1.right, h2.right);
}
// 时间复杂度O(N)
public static int sameNumber2(Node head) {
String algorithm = "SHA-256";
Hash hash = new Hash(algorithm);
return process(head, hash).ans;
}
public static class Info {
public int ans;
public String str;
public Info(int a, String s) {
ans = a;
str = s;
}
}
public static Info process(Node head, Hash hash) {
if (head == null) {
return new Info(0, hash.hashCode("#,"));
}
Info l = process(head.left, hash);
Info r = process(head.right, hash);
int ans = (l.str.equals(r.str) ? 1 : 0) + l.ans + r.ans;
String str = hash.hashCode(String.valueOf(head.value) + "," + l.str + r.str);
return new Info(ans, str);
}
public static Node randomBinaryTree(int restLevel, int maxValue) {
if (restLevel == 0) {
return null;
}
Node head = Math.random() < 0.2 ? null : new Node((int) (Math.random() * maxValue));
if (head != null) {
head.left = randomBinaryTree(restLevel - 1, maxValue);
head.right = randomBinaryTree(restLevel - 1, maxValue);
}
return head;
}
public static void main(String[] args) {
int maxLevel = 8;
int maxValue = 4;
int testTime = 100000;
System.out.println("测试开始");
for (int i = 0; i < testTime; i++) {
Node head = randomBinaryTree(maxLevel, maxValue);
int ans1 = sameNumber1(head);
int ans2 = sameNumber2(head);
if (ans1 != ans2) {
System.out.println("出错了!");
System.out.println(ans1);
System.out.println(ans2);
}
}
System.out.println("测试结束");
}
}