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2 years ago
package class36;
import java.util.Arrays;
// 来自腾讯
// 给定一个正数数组arr代表每个人的体重。给定一个正数limit代表船的载重所有船都是同样的载重量
// 每个人的体重都一定不大于船的载重
// 要求:
// 1, 可以1个人单独一搜船
// 2, 一艘船如果坐2人两个人的体重相加需要是偶数且总体重不能超过船的载重
// 3, 一艘船最多坐2人
// 返回如果想所有人同时坐船,船的最小数量
public class Code08_MinBoatEvenNumbers {
public static int minBoat(int[] arr, int limit) {
Arrays.sort(arr);
int odd = 0;
int even = 0;
for (int num : arr) {
if ((num & 1) == 0) {
even++;
} else {
odd++;
}
}
int[] odds = new int[odd];
int[] evens = new int[even];
for (int i = arr.length - 1; i >= 0; i--) {
if ((arr[i] & 1) == 0) {
evens[--even] = arr[i];
} else {
odds[--odd] = arr[i];
}
}
return min(odds, limit) + min(evens, limit);
}
public static int min(int[] arr, int limit) {
if (arr == null || arr.length == 0) {
return 0;
}
int N = arr.length;
if (arr[N - 1] > limit) {
return -1;
}
int lessR = -1;
for (int i = N - 1; i >= 0; i--) {
if (arr[i] <= (limit / 2)) {
lessR = i;
break;
}
}
if (lessR == -1) {
return N;
}
int L = lessR;
int R = lessR + 1;
int noUsed = 0;
while (L >= 0) {
int solved = 0;
while (R < N && arr[L] + arr[R] <= limit) {
R++;
solved++;
}
if (solved == 0) {
noUsed++;
L--;
} else {
L = Math.max(-1, L - solved);
}
}
int all = lessR + 1;
int used = all - noUsed;
int moreUnsolved = (N - all) - used;
return used + ((noUsed + 1) >> 1) + moreUnsolved;
}
// 首尾双指针的解法
public static int numRescueBoats2(int[] people, int limit) {
Arrays.sort(people);
int ans = 0;
int l = 0;
int r = people.length - 1;
int sum = 0;
while (l <= r) {
sum = l == r ? people[l] : people[l] + people[r];
if (sum > limit) {
r--;
} else {
l++;
r--;
}
ans++;
}
return ans;
}
}