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package class29;
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public class Problem_0050_PowXN {
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public static int pow(int a, int n) {
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int ans = 1;
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int t = a;
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while (n != 0) {
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if ((n & 1) != 0) {
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ans *= t;
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}
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t *= t;
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n >>= 1;
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}
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return ans;
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}
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// x的n次方,n可能是负数
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public static double myPow(double x, int n) {
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if (n == 0) {
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return 1D;
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}
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int pow = Math.abs(n == Integer.MIN_VALUE ? n + 1 : n);
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double t = x;
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double ans = 1D;
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while (pow != 0) {
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if ((pow & 1) != 0) {
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ans *= t;
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}
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pow >>= 1;
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t = t * t;
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}
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if (n == Integer.MIN_VALUE) {
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ans *= x;
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}
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return n < 0 ? (1D / ans) : ans;
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}
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}
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