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#!/bin/bash
LeapYear=`date +%Y`
# 方法一
# if [ $[$LeapYear % 400 ] -eq 0 ] ; then
# echo "闰年"
# elif [ $[$LeapYear % 4 ] -eq 0 ] ; then
# if [ $[$LeapYear % 100 ] -ne 0 ] ; then
# else
# echo "不是闰年"
# fi
# 方法二，利用布尔运算实现
if (( ("$LeapYear" % 400) == "0" )) || (( ("$LeapYear" % 4 == 0) && ("$LeapYear" % 100 != "0") )) ; then
echo "闰年"
else
echo "不是闰年"
fi
# 这相当于let语句。如果你尝试类似$ [$ year％400]的东西，你会在这里使用方括号卡住，因为在这里，方括号本身并不代表实际的命令。
