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45 lines
1.2 KiB
45 lines
1.2 KiB
5 years ago
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def digital_to_chinese(digital):
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str_digital = str(digital)
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chinese = {'1': '壹', '2': '贰', '3': '叁', '4': '肆', '5': '伍', '6': '陆', '7': '柒', '8': '捌', '9': '玖', '0': '零'}
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chinese2 = ['拾', '佰', '仟', '万', '厘', '分', '角']
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jiao = ''
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bs = str_digital.split('.')
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yuan = bs[0]
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if len(bs) > 1:
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jiao = bs[1]
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r_yuan = [i for i in reversed(yuan)]
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count = 0
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for i in range(len(yuan)):
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if i == 0:
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r_yuan[i] += '圆'
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continue
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r_yuan[i] += chinese2[count]
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count += 1
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if count == 4:
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count = 0
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chinese2[3] = '亿'
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s_jiao = [i for i in jiao][:3] # 去掉小于厘之后的
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j_count = -1
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for i in range(len(s_jiao)):
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s_jiao[i] += chinese2[j_count]
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j_count -= 1
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last = [i for i in reversed(r_yuan)] + s_jiao
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last_str = ''.join(last)
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print(str_digital)
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print(last_str)
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for i in range(len(last_str)):
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digital = last_str[i]
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if digital in chinese:
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last_str = last_str.replace(digital, chinese[digital])
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print(last_str)
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return last_str
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number = float(input("输入需要转换的数字："))
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if __name__ == '__main__':
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digital_to_chinese(number)
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