def binary_search(arr, target): left = 0; right = len(arr) - 1 while left <= right: mid = left + (right - left) // 2; if arr[mid] == target: return mid elif arr[mid] < target: left = mid + 1 else: right = mid - 1 return -1 def bisect_left(arr, target): """Returns the leftmost position that `target` should go to such that the sequence remains sorted.""" left = 0 right = len(arr) while left < right: mid = (left + right) // 2 if arr[mid] < target: left = mid + 1 else: right = mid return left def bisect_right(arr, target): """Returns the rightmost position that `target` should go to such that the sequence remains sorted.""" left = 0 right = len(arr) while left < right: mid = (left + right) // 2 if arr[mid] > target: right = mid else: left = mid + 1 return left print(binary_search([1, 2, 3, 10], 1) == 0) print(binary_search([1, 2, 3, 10], 2) == 1) print(binary_search([1, 2, 3, 10], 3) == 2) print(binary_search([1, 2, 3, 10], 10) == 3) print(binary_search([1, 2, 3, 10], 9) == -1) print(binary_search([1, 2, 3, 10], 4) == -1) print(binary_search([1, 2, 3, 10], 0) == -1) print(binary_search([1, 2, 3, 10], 11) == -1) print(binary_search([5, 7, 8, 10], 3) == -1) print(bisect_left([1, 2, 3, 3, 10], 1) == 0) print(bisect_left([1, 2, 3, 3, 10], 2) == 1) print(bisect_left([1, 2, 3, 3, 10], 3) == 2) # First "3" is at index 2 print(bisect_left([1, 2, 3, 3, 10], 10) == 4) # These return a valid index despite target not being in array. print(bisect_left([1, 2, 3, 3, 10], 9) == 4) print(bisect_left([1, 2, 3, 3, 10], 0) == 0) # Insert "0" at front print(bisect_left([1, 2, 3, 3, 10], 11) == 5) # Insert "5" at back print(bisect_right([1, 2, 3, 3, 10], 1) == 1) print(bisect_right([1, 2, 3, 3, 10], 2) == 2) print(bisect_right([1, 2, 3, 3, 10], 3) == 4) # Last "3" is at index 3, so insert new "3" at index 4 print(bisect_right([1, 2, 3, 3, 10], 10) == 5) # These return a valid index despite target not being in array. print(bisect_right([1, 2, 3, 3, 10], 9) == 4) print(bisect_right([1, 2, 3, 3, 10], 0) == 0) # Insert "0" at front print(bisect_right([1, 2, 3, 3, 10], 11) == 5) # Insert "5" at back