Simplified some code in QrCode.getAlignmentPatternPositions() in most language versions.

cpp/QrCode.cpp

@@ -506,11 +506,11 @@ std::vector<int> qrcodegen::QrCode::getAlignmentPatternPositions(int ver) {
 		else  // C-C-C-Combo breaker!
 			step = 26;
 		
-		std::vector<int> result(numAlign);
+		std::vector<int> result;
 		int size = ver * 4 + 17;
-		result.at(0) = 6;
-		for (int i = numAlign - 1, pos = size - 7; i >= 1; i--, pos -= step)
-			result.at(i) = pos;
+		for (int i = 0, pos = size - 7; i < numAlign - 1; i++, pos -= step)
+			result.insert(result.begin(), pos);
+		result.insert(result.begin(), 6);
 		return result;
 	}
 }

javascript/qrcodegen.js

@@ -639,11 +639,9 @@ var qrcodegen = new function() {
 			else  // C-C-C-Combo breaker!
 				step = 26;
 			
-			var result = [];
-			for (var i = numAlign - 1, pos = size - 7; i >= 1; i--, pos -= step)
-				result.push(pos);
-			result.push(6);
-			result.reverse();
+			var result = [6];
+			for (var i = 0, pos = size - 7; i < numAlign - 1; i++, pos -= step)
+				result.splice(1, 0, pos);
 			return result;
 		}
 	};

python/qrcodegen.py

@@ -519,10 +519,10 @@ class QrCode(object):
 				step = (ver * 4 + numalign * 2 + 1) // (2 * numalign - 2) * 2  # ceil((size - 13) / (2*numalign - 2)) * 2
 			else:  # C-C-C-Combo breaker!
 				step = 26
-			result = [6] + [None] * (numalign - 1)
+			result = [6]
 			pos = ver * 4 + 10
-			for i in reversed(range(1, numalign)):
-				result[i] = pos
+			for i in range(numalign - 1):
+				result.insert(1, pos)
 				pos -= step
 			return result